How do we slove quadratic equations using the qudratic formula

the formula for a quadratic equation  is ax^2 +bx +. we need to know this before we can  solve it with quadratic formula. so lets get started
Ex://

1.  x^2-6x+5=0
   the first step is find out what are the a,b,and c
   A=1,B=-6,C=5
   now we place them in the quadratic formula x = -(-6)+/-√((-6)^2-4(1)(5))/2(1)
   we will do solve (-6)^2-4(1)(5) 
   (-6)(-6)=36
   -4*5=-20
   36-20=16 we get √16 = 4(perfect square)
   -(-6)=6
   6+/-4/2(1)
   6+4/2=5
   6-4/2=1
   x=5,1
   
2.  3x^2-6x+4=0
   -(-6)+/-√((-6)^2-4(3)(4))/2(3)
   6+/-√(36-12(4))/6
   6+/-√(-12)/6
   we finished (check out the http://jesuslikesmath.blogspot.com/2012/03/how-do-we-use-quadratic-formula.html)

here are some links for help:

• http://ibukmaths.blogspot.com/2011/04/solving-quadratic-equations.html 
• http://www.youtube.com/watch?v=s80J2dAUUyI

How do we use the quadratic formula

to understand how to use a quadratic formula we first have to know what is a quadratic formula. the letter in this equation are from the quadratic equation
 ax^2 + bx +c.

Ex://
 x^2+2x-15=0
A= 1
B= 2
C= -15

x= -2+/-√(2^2-4(1)(-15))/2(1)
we will multiply -4(1)(-15) to get 60
we and 2^2+60 and get 64(this is the discriminant)
-2+/-√(64)/2(1)
-2+8/2=3
-2-8/2=5
x = 3,5

if the discriminant is more the 0 then there is more then one solution
if the discriminant is equal to 0 then there is only one solution
if the discriminant is less then 0 then there is no solutions

 
hope this was helpful for more help check these links below:

• http://www.purplemath.com/modules/quadform.htm
• http://paulpietrzak.blogspot.com/2011/01/solving-quadratic-equations-quadratic.html
• http://www.youtube.com/watch?v=LWyXP3lYlpQ