Saturday, December 15, 2012

How do we use the properties of parallelogram

Parallelogram: A quadrilateral with two pairs of Parallel sides

Properties:
  1. The opposite angel are congruent.
  2. Consecutive angels are supplementary.
  3.  Opposite sides are congruent.
  4. Diagonals bisect each other.
Its never true that the diagonal always congruent
Its never true that the diagonal s are always perpendicular 
Its never true that the diagonal always bisects the angel

For more help check out that links below 

Saturday, December 8, 2012

What are the properties of Kites

Kites -Two pair of consecutive congruent sides
Properties

  1. The Non-vertex angles are congruent
      
  2. Diagonals are perpendicular
  3. The vertex diagonal bisects the other diagonal
  4. The vertex diagonal angle bisector of the vertex angle  
for more help check out these links

Wednesday, November 21, 2012

How do we prove triangle congruent

To prove that triangles are congruent is every easy in many math problems we are always give one or two congruent angles or one or two congruent sides.

 Like the two on the top.
 with the marking that are given to use its easier to prove that they are congruent. 
we can use:
  • SSS (Side Side Side)
  • SAS (Side Angel Side)
  • ASA (Angel Side Angel)
  • AAS (Angel Angel Side)
Reason why SSS,SAS,ASA,AAS< and HL work 

Say we are given
we will need a T-Chart like this one
As you can see line AC≌EC and BC≌DC are both given <ACB≌<EDC is also given but we need to prove it by saying something that will prove it like they are Vertical Angels.Using Side Angel Side we figured out that the two triangles are congruent.

for more help or work check out these links:

Monday, October 29, 2012

how do we use the exterior angle theorem?

To use the exterior angle theorem we have to understand what is an exterior angel is
 Exterior Angel -  triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.
The exterior angle theorem is that the exterior angle is the sum the two opposite angle.

for example say <b 60° and <a is 60° the sum of both those angles will equal <d making it 120° this means that <c is 60° (180°-120°= 60°)

for more help or other examples check out these links below:

Sunday, October 21, 2012

What are the special angel we can create with parallel lines ?


What are the special angel we can create with parallel lines ?
Parallel Lines Are lines that never intersect and have the same slope.
 With these lines we can make angle out of them like: Transversal, Corresponding Angel, Alternate Exterior Angle ,Alternative Interior Angel
  
Transversal - A line that intersects two or more other coplanar line

Corresponding Angel - Angel that are in the same position relative to the transversal and line


 Alternate Exterior Angle - If two parallel like are cut by a transversal  then alternate interior angles are equal
  
Alternate interior angels - If two parallel like are cut by a transversal then alternate exterior angles are equal
    
For more help check out the links below  

Saturday, October 13, 2012

How do we use the special segments in triangles?

Special Segment In Triangles have three main uses Median, Altitude & Angle Bisector 
  • MEDIAN
    - The vertex often angle to the midpoint of the opposite side.
       EX ://  Line1 will go from point C to the middle of A&B (D)
  • ALTITUDE
     - The height of a triangle meets the "ground" at a right angle.
  • ANGLE BISECTOR
    - Bisects on angle in half creating two congruent angles.
      EX :// Line 1 goes from point A1 to T1  both sides are congruent to each other
For more help check these links 

Sunday, April 1, 2012

how do we put all of our quadratic knowledge together?

Now that we know so much about quadratics its time to see what we have learned *if you forgot some of the it don't worry i will post links to my quadratic posted at the bottom each link has more links in them for more help and reviews *
if you remember the formula then this will be easy. if we have x^2+3x-4we want to know what is the Vertex X and Y  intercept and Roots
we first will use the formula  *remember ax^2+bx+c* 
x = -3± √(3^2-4(1)(-4))/2(2)
x=-3± √(9+16)/4
x=-3± √25/4
x=-3± 5/4
we are left with X=-4,1

Vertex:(-2,-6)
X intercept:(-4,0)(1,0)
Y intercept:(0,4)
Roots:(-4,0)(1,0)