Sunday, March 25, 2012

How do we slove quadratic equations using the qudratic formula

the formula for a quadratic equation  is ax^2 +bx +. we need to know this before we can  solve it with quadratic formula. so lets get started
Ex://

  1.  x^2-6x+5=0
    the first step is find out what are the a,b,and c
    A=1,B=-6,C=5
    now we place them in the quadratic formula x = -(-6)+/-√((-6)^2-4(1)(5))/2(1)
    we will do solve (-6)^2-4(1)(5) 
    (-6)(-6)=36
    -4*5=-20
    36-20=16 we get √16 = 4(perfect square)
    -(-6)=6
    6+/-4/2(1)
    6+4/2=5
    6-4/2=1
    x=5,1
  2.  3x^2-6x+4=0
    -(-6)+/-√((-6)^2-4(3)(4))/2(3)
    6+/-√(36-12(4))/6
    6+/-√(-12)/6
    we finished (check out the http://jesuslikesmath.blogspot.com/2012/03/how-do-we-use-quadratic-formula.html)
here are some links for help:

How do we use the quadratic formula




to understand how to use a quadratic formula we first have to know what is a quadratic formula. the letter in this equation are from the quadratic equation
 ax^2 + bx +c.

Ex://
 x^2+2x-15=0
A= 1
B= 2
C= -15

x= -2+/-√(2^2-4(1)(-15))/2(1)
we will multiply -4(1)(-15) to get 60
we and 2^2+60 and get 64(this is the discriminant)
-2+/-√(64)/2(1)
-2+8/2=3
-2-8/2=5
x = 3,5
if the discriminant is more the 0 then there is more then one solution
if the discriminant is equal to 0 then there is only one solution
if the discriminant is less then 0 then there is no solutions
 
hope this was helpful for more help check these links below: