if you remember the formula then this will be easy. if we have x^2+3x-4we want to know what is the Vertex X and Y intercept and Roots
we first will use the formula *remember ax^2+bx+c*
x = -3± √(3^2-4(1)(-4))/2(2)
x=-3± √(9+16)/4
x=-3± √25/4
x=-3± 5/4
we are left with X=-4,1
Vertex:(-2,-6)
X intercept:(-4,0)(1,0)
Y intercept:(0,4)
Roots:(-4,0)(1,0)
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